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	<title>
	Comments on: 260W Power Audio Amplifier	</title>
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	<link>https://amplifiercircuit.net/260w-power-audio-amplifier.html</link>
	<description>Amplifier Project Schematic Diagram</description>
	<lastBuildDate>Sat, 05 Jan 2019 04:09:16 +0000</lastBuildDate>
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		<title>
		By: TheAstro30		</title>
		<link>https://amplifiercircuit.net/260w-power-audio-amplifier.html#comment-26276</link>

		<dc:creator><![CDATA[TheAstro30]]></dc:creator>
		<pubDate>Sat, 05 Jan 2019 04:09:16 +0000</pubDate>
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					<description><![CDATA[Well, I tested it (only at +/-30VDC) and got an output power of around 60W peak. That was using TIP3055/TIP2955 as ouput devices instead of the Darlington ones. Having said that, Darlington transistors would not constitute higher power, rather higher current handling capabilities. So, I&#039;m not sure how you calculated it&#039;s output power, but I&#039;m assuming you did P=V*I, so you took the output p-p swing and multiplied it by it&#039;s current draw. This would be incorrect. The calculation is P=(Vpeak^2)/R, so half the p-p voltage squared divided by the output load. Secondly, I have no idea why you have a 10R/5W resistor in series with the output before the speaker, without an inductor coil. This serves no purpose except introducing distortion, unless you were attempting to use it for short-circuit protection. Finally, I also have no idea why you&#039;re using a 5W 10R resistor in the Zobel network, a 1W devices will be sufficient. That aside, the frequency response is good and produces a nice power of 50W (not 260W) which is clean.]]></description>
			<content:encoded><![CDATA[<p>Well, I tested it (only at +/-30VDC) and got an output power of around 60W peak. That was using TIP3055/TIP2955 as ouput devices instead of the Darlington ones. Having said that, Darlington transistors would not constitute higher power, rather higher current handling capabilities. So, I&#8217;m not sure how you calculated it&#8217;s output power, but I&#8217;m assuming you did P=V*I, so you took the output p-p swing and multiplied it by it&#8217;s current draw. This would be incorrect. The calculation is P=(Vpeak^2)/R, so half the p-p voltage squared divided by the output load. Secondly, I have no idea why you have a 10R/5W resistor in series with the output before the speaker, without an inductor coil. This serves no purpose except introducing distortion, unless you were attempting to use it for short-circuit protection. Finally, I also have no idea why you&#8217;re using a 5W 10R resistor in the Zobel network, a 1W devices will be sufficient. That aside, the frequency response is good and produces a nice power of 50W (not 260W) which is clean.</p>
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